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<br />- <br /> <br />BOTAS ENGINEERING, INC. <br /> <br />Job Sunny Isles Restaurant <br /> <br />Consulting Engineers <br /> <br />- <br />Sheet No. of <br /> <br />Calculated by DBC Date 5/2010 <br /> <br />Patricia M. Botas - Florida License # 41829 <br />7875 NW 12th Street, Suite 120 - Miami, FL 33126 <br /> <br />Checked by PMB Date 5/2010 <br /> <br />4.4. Floor Slab (Ramp) - One Way Slab - Flexural AnalysIs <br /> <br />- 5lab's 5pan lengths: <br />- Recommended 51ab depth <br /> <br />L:= 13ft + Oln <br /> <br />Deflection Coefficient : <br />ACI 9.5(b). Maximum Permissible Computed Deflection <br />Solid One-way Slabs <br /> <br />coeff := 3GO <br /> <br />Minimum slab depth : <br /> <br />-I <br />dprop:= I 2L. coeff <br /> <br /> <br />- Materials and 5ectlon Data <br /> <br />Cross Section : <br /> <br />Concrete : <br /> <br />Depth of Slab: dt:= 81n <br /> <br />Strength: fc:= 5500pSl <br /> <br />Remforcmq Steel : <br />Yield Strength: fy:= GOKsI <br /> <br />Width of Slab : <br /> <br />b:= 121n <br /> <br />Weight of <br /> <br />concrete : <br /> <br />wc := I 50pcf <br /> <br />Clear rebar <br />cover : <br /> <br />cov := 2.01n <br /> <br />- 51ab Loads <br /> <br />Dead loads <br /> <br />Self-weight: <br /> <br />wslab.5W := wcdt <br /> <br />wslab.5W = 100 pst <br /> <br />Supenmposed DL : <br /> <br />WSDL :=25psf <br /> <br />WSDL = 25 psf <br />WDL.S = I 25 psf <br /> <br />Uniformly distributed DL : <br /> <br />WDL.S := Wslab.5W + WSDL <br /> <br />live loads <br /> <br />Uniformly dlstnbuted LL : <br /> <br />WLL.S := I oopst <br /> <br />WLL.S = I 00 pst <br /> <br />Span Bendmq Moments <br /> <br />Span Moment DL : <br /> <br />MDL := 8- 1 . WDL.S' L2 <br />M -I L2 <br />LL := 8 . WLL.S . <br /> <br />-I <br />MDL = 2.G (Kip ft) . tt <br />-I <br />MLL = 2.1 (Klpft) . ft <br />-I <br />Mu = G.5 (Klpft) . ft <br /> <br />Span Moment LL : <br /> <br />Ultimate Moment : <br /> <br />MU:= 1.2' MDL + I.G' MLL <br /> <br />Span Flexure DeSign <br /> <br />DIameter of proposed bottom lonqltudmal remforcement : <br />Bar := 5 dr:= Bar. 8- 'In dr = O.G In Abar:= 0.0 122. (Bar In) 2 <br /> <br />2 <br />Abar = 0.3 I In <br /> <br />DIstance from exterior compressive fiber to <br />centrOid of tensional remforcement : <br /> <br />d := dt - O.5dr - cov <br /> <br /> <br />73 <br />